high school chemistry homework help

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Number of high school chemistry homework help Topics: 5

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100% Q: high school chemistry homework help plz?

the question is asking a 100.0 grams of iron at 0.0 degrees celcius absorbs 330 calories of heat. wwhat is it's final heat. i used q=smAt. i ended up with 19 degrees celcius . could u check if im right. i no doing it is like a hassle but could u help me out plz

A:100 grams of irong at 0 degrees C would be 32 degrees F for the temperature. 100g. at 0C absorbs 330. I think that's right...I'm not positive though...

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100% Q: Help with High school Biology homework over chemistry?

3 question are they true or false and if they are false what is the right answer....... On Earth, NINETY elements occur naturally. only four elements-CARBON, HYDROGEN, OXYGEN, AND NITROGEN- make up more than 96% of the mass of a human trace elements such as iron and magnesium are present in living thening in VERY LARGE amounts all of the capital words are the ones that if they are false need to be changed

A:you got me!!! I think is 92 naturally occurring elements...uranium being the last... CHON is what proteins and humans are mostly made of..i would agree with that trace elements...VERY SMALL amounts...seems self-answering there... good luck

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100% Q: Homework Help on High School Chemistry?

one important way in which solutions of known molality have proved useful to chemists in studying the effects of solutes on solvents? thanx

A:Lancenigo di Villorba (TV), Italy At the middle of XIX century, a frech scientist (F. M. Raoult) remarked that SALT's Aqueous solutions exercite a LOWER VAPOUR PRESSURE THAN Deionized Water does. In the second half of XIX century, scientists discovered that SALT's Aqueous solutions show HIGHER BOILING POINT THAN Deionized Water does. Moreover, they remarked that SALT's Aqueous solutions show LOWER FREEZING POINT THAN Deionized Water does. The Solute's Action in the solution resulted related to these remarks, so the scientists thought that they are the overcomes of the same interaction. The Science's History determined that here it begun the "COLLIGATIVE PROPERTY's THEORY". DISCUSSION The Data's Correlations gave a Mathematical Correspondance DeltaT = K * cm that is the TEMPERATURE's CHANGE results proportional to SOLUTE's MOLALITY. I remember you that MOLALITY is a Solute's Measure Molality = Solute-Mole's Number contained in 1 kg. Solvent's Mass Scientists determined the "K" as a Constant depending on SOLVENT's NATURE only : it exists a "Kfreezing" 's value and a "Kboiling" 's value for any solvent. I hope this could be clear.

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100% Q: Any Chemistry Whizzes wiling to help me with High School homework?

Okay.. so any takers? i have a couple of sample questions..and i really don't quite get some things.. its mostly Conversion and things..i need examples and explanations.. a textbook measures 250. mm long, 224 mm wide, and 50.0 mm thick. It has a mass of 2.94kg. a. what is the volume of the book in cubic meters? b. what is the density of the book in grams per cubic centimeters? c.what is the area of one cover in square meters?

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100% Q: Chemistry homework help (I always choose a best answer)?

These are the questions I'm stuck on in my high school chemistry homework. Help with any of these would be great!! 1) How many kg of air are in a room sized 52,669.44cm^3 (cubed) if the density of air is .00118g/cm^3? 2) 2Al(s) + 3Cl2(g) ---> 2AlCl3 (s) You are given 10 g of Al and 17 g of chlorine gas, if you have extra chlorine, how many moles of AlCl could be produced from 10g of Al? 3) 60.0mL of KOH is titrated against H2SO4. What is the molarity of KOH if 18.2mL of 1.5 M H2SO4 is needed? 4) How many grams of Na3PO4 will be needed to produce 450mL of a solution with a concentration of Na+ ions of 1.4 M? 5) CO(NH2)2 (liquid) ---> HNCO (liquid) + NH3 (gas) What mass of melamine will be obtained from 114.5 of urea if the yield of the overall reaction is 84.0 ?

A:1) Make your units all cancel. In this case, the cm^3: 52, 669cm^3 x 0.00118g/cm^3 = 62.14942g or 0.621494Kg 2) Find the limiting reagent then use the ratio to calculate. You're told the limiting reagent is Al: 10g Al x 1mol/27g x 2AlCl3/2Al = 0.4moles AlCl3 3. Make a balanced equation and solve: 2KOH + H2SO4 --> 2H20 + K2SO4 1.5M/LH2SO4 x 0.0182L x 2KOH/1H2SO4 x 1/.060L = .91M/L KOH 4. Convert to moles, moles to grams and solve: 1.4M/L x 0.450L x 164g/mole = 103.32g 5. I don't know what units this is in. Can't help, sorry.

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