algebra math problems

A:Problem 1: Let D = distance that Sheila travels one way X = current of the river Tu = time for Sheila to negotiate the distance upstream Td = time for Sheila to negotiate the distance downstream Your working equations are: D = (2 - X)Tu --- Sheila going upstream D = (2 + X)Td --- Sheila going downstream Tu = 4/(2 - X) Td = 10/(2 + X) Since Tu = Td, (4/(2 - X)) = (10/(2 + X)) Solve for X in the above equation. Problem 2: Let D = distance between Detroit and Columbus From Detroit to Columbus, D = 60T1 where T1 = time it took Mrs Smith to drive from Detroit to Columbia From Columbia to Detroit D = 55T2 where T2 = time it took Mrs Smith to drive from Columbia to Detroit Equating the 2 formulas for "D", 60T1 = 55T2 and since T2 = T1 + 0.33 60T1 = 55(T1 + 0.33) Solve for T1 and substitute this calculated value in the equation D = 60T1 to determine the distance between Detroit and Columbus.

A:9k + 7k -4g= 8 x g solve for anything u want Use cross products to determine which ratio forms a proportion with 2/5. Simplify the expression 12n + (-5n) + 3n. Simplify 14q + 6 + 3q. It costs $7.50 to park a car or van at the Family Fun Amusement Park. The admission price to the park is $22.50 per person. If a group in one vehicle spends $142.50, how many people went to the park? Solve 6r – 2r + 15 = -25.

A:10+3(x+2)=31 10+3x+3*2=31 10+3x+6=31 16+3x=31 add -16 to both sides to get 3x=15 divide both sides by 3 to get x=5 _______________________- -2(x-6)+7=35 -2x-2*(-6)+7=35 -2x+12+7=35 -2x+19=35 add -19 to both sides to get -2x=16 divide both sides by -2 to get x=-8 _______________ 187=19+7(13-x) 187=19+91-7x 187=110-7x add -110 to both sides to get 77=-7x divide both sides by -7 to get x=-11 __________________ 20=14+3(x+8) 20=14+3x+24 20=38+3x add -38 to both sides to get -18=3x divide both sides by -3 to get x=-6 ______________ -5(2x-7)+24=89 -10x+35+24=89 -10x+59=89 add -59 to both sides to get -10x=30 divide both sides by -10 to get x=-3 _______

A:1. Add B to both sides and Multipy both sides by x leaving you... a=bx+cx/y 2. Multiply the 2x over x minus 3 by (x+3) Distribute the 2x. and Add. [Because x^2-9 = (x+3)(x-3)] ANSWER: 2x^2+6x+3 all over (x+3)(x-3) OR 2x^2+6x+3 all over (x-9) 3. HINT* anything to the powe of 0 is 1 (one)

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